where the line crosses the Y axisThe X and Y intercepts and the Slope are called the line properties. P can lie in. ----- y-intercept To find the y-intercept, plug in and solve for y Start with the given equation. harry m. Lv 6. parallel means to have the same slope but different y-intercept. Multiply … Favorite Answer . First, get the original line in y = mx + b form: 5y = 3x - 3. y = 3/5 x - 3/5. Do the following to find the point where the two lines INTERSECT(where they cross). x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. x+y=0, 3x-y+2=0, y+1=0, y=0. asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) Find the equation of a straight line passing through the intersection of 2x + 5y – 4 = 0 with x-axis and parallel to the line 3x – 7y + 8 = 0. x and y intercept of straight line 3x-5y=15? The co-ordinates of two points E and F are (0, 4) and (3, 7) respectively. Q.12 A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4th quadrants (4) 1st quadrants Ans. So we have two sample points #(0,15)# and #(5,0)# Since #3x+y=15# is a linear equation, we only need two points to establish the graph. Graph the linear function d(x)=−1/2x−3 I need to know … 104. C is the - the answers to estudyassistant.com Find the equation of the line. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. B is the reflection of A in the line y = x. ~~~~~ There is a remarkable formula to calculate the distance from a given point to a given straight line in a coordinate plane. A straight line l 1 with equation x-2y+10=0 meets the circle with equation x 2 + y 2 = 1 0 0 at B in the first quadrant. Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept: -3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN), Beginning Algebra Tutorial 11: Simplifying Algebraic Expressions. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. y= 3/5x-3. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. If you are unable to turn on Javascript, please click here. Draw QN parallel to x-axis meeting y-axis at N. So, y = ON = -6. For any pair of mirror points on the given line, the midpoints of their tangent chord line are also mirror points. P can lie in Let the straight line in a coordinate plane is defined in terms of its linear equation a*x + b*y + c = 0, where "a", "b" and "c" are real numbers, and let P = ,) be the point in the coordinate plane. 0 votes. Let the equation of a line is 3x + 5y = 15 and a point P on this line is equidistant from x and y axis. The equation is, ax + by + c = 0; so, in intercept form it … So, every first degree equation in x and y represents a straight line. Relevance. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. QED. Closest point will be on the perpendicular from (2,5) to the line. 106. 9 Graphing equations in different forms. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Simplify. Question 17. A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . Hint. Equation of the given line is x cos 30° + y sin 30° = 2 y sin 36° = -x cos 30° + 2. Intercept form of a line is ⇒ (∴ a = b) ⇒ x + y = a ⇒ y = – x + a ∴ Slope is – 1 Hence, the correct option … Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. Consider the lines given by 2x-3y = 12 and 3x + 5y =15. Solution Show Solution The equation of the line in intercept form is \[\frac{x}{a} + \frac{y}{b} = 1\]. Answer to: Use the intercepts to graph the equation 3x-5y=15. In which quadrant the point P lies? (3) Solution. If a straight line passing through the point P(–3, 4) is such that its intercepted portion between the coordinate axes, A straight line L at a distance of 4 units from the origin makes positive intercepts on the coordinate axes and the perpendicular from the origin to. Favorite Answer. 1 answer. Solution Show Solution. Question 16. Anonymous. Given that two lines are perpendicular, Given a straight line with equation coefficients as a, b & c(ax + by + c = 0), the task is to find the area of the triangle formed by the axes of co-ordinates and this straight line.. x-intercept To find the x-intercept, plug in and solve for x Start with the given equation. (C) a straight line with slope 1 and x intercept 3. ANS: x + y - 1 = 0 PTS: 1 REF: The Equation of a Straight Line 4. A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4 th quadrants Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. 15=3x. The straight line x + 2y = 1 meets the coordinate axes at A and B. Yes, the line 3x = y + 1 is the bisector. Show that the straight lines 2x-3y=6 and 4x-6y = = 25 are parallel, and find the distance between them. 6.4 19-45 odds ; Due Wednesday 1/14/04 ; 6.5 13-25 … Question 15. Take a point P on the left of y-axis such that the distance of point P from the y-axis is 2 units. The relation between variables x, y satisfy all points on the curve. Find the equation of the line. ... Now draw a straight line through the plotted points to graph . use point- slope form to get the equation of the line: y - 5 = -5/3(x - 2) y = -5/3 x + 10/3 + 5. y = -5/3 x + 25/3. Add your answer and earn points. 1. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. Slope of 3x+4y-5 = 0 is = -3/4. ... Find the parallel line using the point-slope formula. … Question 15. (C.B.S.E. Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). 2 Answers. Lv 7. P can lie in - Sarthaks eConnect | Largest Online Education Community A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. Example 18 Find the distance of the point (3, –5) from the line 3x – 4y –26 = 0. 3x+5y=15 Geometric figure: Straight Line Slope = -1.200/2.000 = -0.600 x-intercept = 15/3 = 5 y-intercept = 15/5 = 3 Rearrange: Rearrange the equation by subtracting what is to the ... 3x+5y=16 3 x + 5 y = 1 6 A circle is drawn through A, B and the origin. Plug in . Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get: Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. Find the equation of a straight line parallel to the line 2x +3y = 5 and having the same y-intercept as x +y +4 = 0. 3x + 5y = 18. First isolate y to get standard form:-5y=-3x+15. What is the midpoint of the line segment between the two points (-3, 2) and (4, 0)? Draw PQ parallel to y-axis cutting the line y = 3x at Q. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. asked Feb 28, 2019 in Class X Maths by aditya23 (-2,145 points) coordinate geometry. Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: Find Any Equation Parallel to the Line y=-3x+5. 1 decade ago. your y-intercept is (0,-3) because the "b" (y=mx+b) is -3. Thus, equation to straight line is 3x – 4y + 5 = 0 (iii) Equation of line parallel to line 2x + 5y = 7 2x + 5y = c …(i) Mid point of line joining the points (2,7) and (-4, 1) Putting this value in equation (i), ⇒ 2 × (-1) + 5 × (4) = c ⇒ -2 + 20 = c ⇒ c = 18 Thus, Required equation of line is 2x + 5y = 18 (iv) Equation of line passing through the points (- 3, 7) and (5, – 4) Equation of line perpendicular to this line 11y – 8x … So the x-intercept is . b= y-intercept. Plot points (1,3) and (2,6) on a graph paper and join them to get the required graph. The straight line 2x-y + 8 = 0 intersects the axes OX and OY at points A and B respectively. Find the Distance of the Point (4, 5) from the Straight Line 3x − 5y + 7 = 0. Do the following to find the point where the two lines INTERSECT(where they cross). The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3, 2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. Given a straight line x cos 30° + y sin 30° = 2. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. ∴ m = 3. Question 15 8 Answers. 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! Such an equation is usually written y=mx+b ("y=mx+c" in the UK). C = 15. the desired line is : 3x + 4y + 15 = 0 Note that the configuration is symmetric with respect to the line passing through origin and perpendicular to $3x-4y+12=0$. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. A straight line passes through the point (3, 2) and the portion of this line, intercepted between the positive axes, is bisected at this point. Plot the points and the straight line. 4x-3y = 17 .Answer. Question By default show hide Solutions. 3x+5y=15 Geometric figure: Straight Line Slope = -1.200/2.000 = -0.600 x-intercept = 15/3 = 5 y-intercept = 15/5 = 3 Rearrange: Rearrange the equation by subtracting what is to the ... 3x+5y=16 3 x + 5 y = 1 6 What best explains the fact that there are very few averages in the lowest class? Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. 1 0. esperism. Point slope form of above is y= -3x/5 + 15 Answer Save. … Knowledge required: General equation of a line is y=mx+c. (a) Solution. Find the equation of a line passing through (3, – 2) and perpendicular to the line. Find the co-ordinates of P. Also, find the equation of the line through P and perpendicular to the line 5x – 3y + 4 = 0. how steep the line isb is the Y-intercept i.e. i have no idea how to do this. 105. We shall now graph the line  3x+5y-15  = 0 and calculate its properties, Notice that when x = 0 the value of y is 3/1 so this line "cuts" the y axis at y= 3.00000, When y = 0 the value of x is 5/1 Our line therefore "cuts" the x axis at x= 5.00000, Slope is defined as the change in y divided by the change in x. We know that distance (d) of a point (x1, y1) from a line Ax + By + C = 0 is d = |_1 + 〖〗_2 + |/√(^2 + ^2 ) Now, our equation is 3x – 4y – 26 = 0 The above equation is of the form Which graph represents -3x+5y=-15? Let PQ be the straight line having AB, the line segment between the axes. Show that the straight lines 2x-3y=6 and 4x-6y= = 25 … Find the equation of the line which is parallel to 3x -2y -4 = 0 and passes through the point (0, 3). Find the equation of the straight line passing through the point (2, 1) and bisecting the portion of the straight line 3x − 5y = 15 lying between the axes. See answer jf9375254 is waiting for your help. What is the general form of the line y = - x + 1? we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. Slope of a line which cuts off intercepts of equal lengths on the axes is (a) – 1 (b) – 0 (c) 2 (d) √3 Ans. Q.16. a. rewrite each line in slope-intercept form. Multiply and 0 to get 0. Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: x = 5t y = -3t+3 ; t ∈ R Slope: m = -0.6 Slope angle of line: φ = -30°57'50″ = -0.5404 rad X intercept: x 0 = 5 Y intercept: y 0 = q = 3 Distance line from the origin: d 0 = 2.5725 The length of the segment AB: |AB| = 5.831 Vector: AB … = ( -5,6 ) and multiply 3.2 and then calculate it to get the x-intercept. 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